I am still unsure of the math being sugguested that claims you have a higher chance of picking the correct door, despite there being only 2 to choose from.
to put this simply and for those who cant be bothered watching the video;

>you are given a selection of 3 doors.
>behind one of those doors, is the prize.
>the other 2 doors is nothing
>select the door you think the prize is behind (33.3% chance of success)
>host reveals a door that has nothing leaving only your selection, and the other door unopened.
>gives you the option of changing your mind and selecting the other door.


Apparantly, math and logic says that the odds of it being in the door you did not select, is higher than the one you intially picked because when you picked it before one of the doors with nothing was eliminated from the equation, you had a 33% chance of success. By now having the option to choose between 2, you increase your odds of because now you are only picking between 2, but ONLY if you choose the door you didnt pick.

the video explains in more detail, but I cannot fathom it.