I propose that the only real letter of importance in Abrahadabra, is the letter "A". If Abrahadabra is spelled out, as it often is, in an inverted cone, then consider the following:
1|2|3|4|5|6|7|8|9|10|11
__________________
A-B-R-A-H-A-D-A-B-R-A
A-B-R-A-H-A-D-A-B-R(1)
A-B-R-A-H-A-D-A-B
A-B-R-A-H-A-D-A
A-B-R-A-H-A-D(4)
A-B-R-A-H-A
A-B-R-A-H(6)
A-B-R-A
A-B-R(8)
A-B
A
(11)
* There are eleven letters in the word Abrahadabra.
* There are five columns/diagonals of the letter A in the cone/pyramid diagram.
* The spaces(other unimportant columns) between the columns/diagonals of A are: 2,1,1,2(A2A1A1A2A) The sum of which is six.
* There are a total of 30 A's.
* Add the total number of As with the number of spaces in between and we receive 36(or six squared)
* Divide the total number of A's(30) by the number of spaces inbetween and we're back to 5.
* If you number all the columns/diagonals starting from left to right you'll notice that the columns of A's appear on the 1st, 4th, 6th, 8th and 11th.
* 1, 4, 6, 8, and 11 totaled is 30(or 5X6).
* Six A's appear on Column 6.
* The total number of letters appearing in the pyramid/cone are 66. Which is of course 6X11.
* If you subtract all the A's(30) from the total number of letters appearing in the pyramid(66), you again arrive at 36(or six squared)
* If you take the number of A columns(5) and times them by the number of remaining columns(6) you arrive back at 30.
* If you add the number of A columns(5) and the number of remaining columns(6) you get eleven.
* Also if you tally all the non-A letters together, you will reach 36.
* Also if you multiply together all the amounts that each A Column decreases by(3X2X2X3) You will get 36.
* Consider that the Columns/diagonals in which the "A"s appear are 1, 4, 6, 8 and11.
* Consider that the Rows in which A's begin and end the row are 1, 4, 6, 8 and 11.
* The number of A's that occur in the A columns/diagonals are 1, 4, 6, 8 and 11.
* Added together, these total to 30(or 5X6).
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